O.k., o.k., I know—I've left you Surf—well, if you're PERSIL (purse'll) stand it—your LUX in !

LOST AND FOUND.—Continued.

You apologise to the audience, remove the clothes from the boy and with a suitable small gift send him back to his seat amidst thunderous applause which he will receive. You now proceed to the trick which will eventually produce the missing ring.

Now there is one thing which I cannot stress too much and that is this. The laughter, as you can imagine, comes from the "business" with the eggs, therefore timing is most essential as are facial expressions. I have not given you any patter, but needless to say, you will come out with the odd crack while producing eggs, which suits your style and fits the occasion. If there is any point about which you are not clear in this routine, I will be only too pleased to clear it up for you. Merely drop a note to the Editor who will pass it on to me. My reason for stating this is that this is the type of effect which will either go over really big or die a death, and with good timing and practice, the former should bring you wonderful applause at the final curtain. Practise with rubber eggs or even balls of paper, BUT, do have at least one practise with the real eggs, you can always use the kid next door who will be only too pleased to help.

One thing which I have not mentioned. Have a wet cloth and a towel handy, so that a quick rub and drying, brings the kid's hands back to normal . . . and he returns to his seat none the worse.

The Floating Pips or 3-D Magic


The following original idea I have made up and worked quite successfully. It can be made up at very little expense and yet the effect is something of a small illusion.

The effect is as follows. The magician shows a small box about the size of the container for a pack of cards. The box has a glass window in the front and a small tag underneath. See Fig. 1. The box is now pressed into a container into which it fits exactly. See Fig. 2.

The box is obviously empty.

Then three cards are freely selected from a pack by three members of the audience. The performer then calls for the first card chosen—it is the Ace of Hearts. He then opens the lid of the cover and blows a little smoke from his cigarette into the box. The box is pulled down and one pip —a Heart—is apparently floating in the centre of the box. The box is then pushed into the cover again.

The second card is called for, this is the Five of Hearts. Again smoke is blown into the box and this time five pips are seen floating inside the box. The process is then repeated for the third card chosen, which is a court card. Finally, the box and the cover are handed out for examination.

METHOD.—The effect is brought about by means of a thin fake which is made of celluloid in three sections and a white card which is moved between these sections.

A heart is painted in the middle of the first section, four hearts on the second, and a representation of a court card on the last. Notice also that the edge of the top of the fake, for each successive section, is slightly lower than the one before. This is because a white card is slid under cover of the action of opening the lid, from one section to the other revealing each layer in turn, and the shape of the top of the fake facilitates this action.

To commence, the white card is in front of the fake covering the ace. In this position the box can quickly be shown to be empty. The box is now pushed up into the cover. The lid of the cover opened, smoke blown in, and by holding the white card against the inside parts of the open lid with the thumb and pulling the box down a short way the card is levered from in front of the ace to just behind it. This action may be tricky but an endeavour should be made to pull down the box as smoothly as possible. Naturally, to produce the five hearts it is only necessary to do the same thing, this time moving the white card behind the second section of the fake. The same movement for the court card.

Finally, the fake and white card should be secretly dropped behind something on your table before handing out the box and cover for examination. Also the three cards of course, have to be forced in your favourite manner.

Vampire Club Meets Again



Right Out of "Ravelli's" Depth

In his "Skull Shakers" No. 6 (No. 2. Vol. 4. May. 1955), Peter A. McDonald said he hoped that someone will chew the whole thing over and let him have the benefit, if they crack the problem. And that's just what I intend to do now.

For years I have worked with this principle and now know quite a lot about it, and furthermore I have examined the principle mathematically, and so I can say to you now, that (a) it always works and (b) why it always works.

First the conditions for the number. The conditions can be set in many different ways, but 1 found the following the best way.

Any number of three digits can be used, with the only condition, that the last digit is at least two greater or two smaller i.e. 375 or 816. But the last digit may be any number greater than the first, just at least two.

With this condition, you have many advantages. You must not say that the three digits must be different, for the number 335 or 855 works equally as well as any other and second and more important, after the subtraction there is ALWAYS a number of three digits left, so you must not stumble over this difficulty.

Now for the reason why it works. After the first subtraction you get a three digit number with the following particularities : the middle digit is always nine and the two end digits added together make nine too.

Why this is so, it would be too difficult to explain in short. So I will just explain why the middle number is always 9. When you subtract the two numbers, you always subtract the middle number from itself, for the position of the middle number is not changed when you reverse the original number, and this leaves zero, nothing. But at the last digit you subtract a greater number from a smaller, and so you have to take one away from the foregoing column and that leaves 9 instead of zero.

Now when you multiply this resulting number by any number between one and ten, the resulting three or four digit number has again the same character.

The three digit number: The middle number is 9 and the two end digits add to 9.

The eventual four digit number : The first and third digit add to 9 and the second and fourth add to 9. Now you see why e.g. the number 5526 does not work. Because the above is not true. And so it is certain, that you cannot arrive at 5526 by the foregoing processes.

And now, why the total is always 81. This is very easy to understand, but difficult to describe. I will do it only with the four digit number, the proof with the three digit number is analog. This is our number :—

A B C D, where A and C totals 9 and B and D totals 9.

Now you multiply A with B and B with C. In both cases one factor is B. You could do the multiplication by first adding A and C and then multiplying with B: A.B + C.B = B (A +C). A and C is 9, so you now have 9 times B.

Then you multiply C and D and D with A. Again you could first add C and A and then multiply with D: C.D. + D.A = D (C + A). A and C is 9 so you have in fact 9 times D. In the whole you now have 9 times B and nine times D. Again you can add B and D and then multiply with 9: 9.B + 9.D = 9 (B + D). But B and D is also 9, so that what is left is 9 times 9, and this is evidently 81. And that is the proof that you always get 81 and that no other number is possible. The whole proof is based on the fact that 2 times 9 and seven times 9 is equal to nine times nine.

Other Stunts with the same Principle 1, The 1089 Stunt

This stunt is very surprising, for you haven't to ask any question during the whole experiment.

The spectator chooses any three digits number, with again the only condition, that the last digit is at least two different from the first one. Next he is to reverse this number and subtract the smaller from the greater one. This is exactly as in the 81 Stunt.

But now he is to again reverse the resulting number and add it to the one reversed. And he is to concentrate on the result. And this will always be 1089, which you can reveal dramatically.

Example: 772-277=495+594=1089.

Again it is very easy to show why. After the subtraction, you have a number with 9 in the middle and the two others adding to 9. After again reversing, the two end digits add to 9, the middle digits to 18 and the first digits again to 9. See our example :

495 + 594 5 and 4 is 9, 4 and 5 is 9, and 9 and 9 is 18.

When you add, 9 you always get 1089. 18

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