Correction
In Expert Card Technique, a mention is made of the Chart of 17. The 48 cards mentioned and the 17 cards apart is in error.
Also, it is erroneous for 52 cards as there are 17 cards between the last card at the bottom and first card at the top; after that, there are only 16 cards between 1st and 2nd cards and 2nd and 3rd cards in the chain of three.
have the exact number of cards between each card of a set of three, you need to use an odd number of cards such as 51 cards and an Out Shuffle by making sure the smaller half, that is
25 cards are weaved into the larger half, 26 cards, so that the top and bottom cards of the 26 card packet always remain the top and bottom cards of the
26 card packet after the shuffle.
It also follows that no matter how many times you cut the pack the three cards will remain the same distance from each other around the clock so to speak.
It also is easy to realize that there are other sets of threes that are likewise separated by the same number of cards between them and continue to remain thus separated even though the pack is cut between each shuffle.
You can also realize how the number 17 was arrived at because 51 divided by 3 is 17. It also follows that any odd number of cards if divisible by 3 will give you a different number other than 17 and will give the same results. The number of Faro Shuffles needed to get the packet back into the original order will change.
If one set of three cards, in a 51 card deck, remain constantly in the same relation to each other regardless of shuffles in an odd pack, it follows that all the other sets of three will also retain the same relationship despite shuffles and cuts between each shuffles. After eight such shuffles, the cards will return to their original order except for the top card. You will have to locate your original top card, and cut it to the top, to get the original order from the top down.
One more thing, it doesn't make any difference whether the larger half ends up in the left hand or right hand as long as the smaller half, 25 cards, is weaved into the larger half, 26 cards.
This, is the basic principle of the
Chart of Seventeen as unfortunately misdetailed in Expert Card Technique.
However, other things of interest listed in Expert Card Technique are the Endless Belts which show how six groups of eight cards each move through the deck. Also the fact that the 18th and 35th cards are exchanged, or move between themselves during each perfect Out Shuffle. Their study is recommended.
[Note: What Hugard and Braue actually said in Expert Card Technique was that "Each of these cards was originally sep arated from its fellows by 17 degrees; after a shuffle, each card remains separated by 17."
This is true, in that counting 17 cards past a given card will discover the same card that was 17 cards past before the shuffle. There are 16 cards between these cards, and the 17th card counted is the same as before the Faro.
A 52nd card does prevent this count from continuing from the bottom of the deck to the top (unless you count 18 instead of 17). However, since an Out Faro is always used, the bottom card never changes. The extra card just goes along for the ride, ed.]
Here is an idea which enables one to get the full benefit of an odd pack, 51 cards, shuffled without the necessity of discarding the one card. In other words, you get to cut the pack between each shuffle, stick to Out Shuffles and at the end of 8 shuffles, the pack will be in the original order. It makes use of the Mario Cover Up Cut as explained in the Throw Off Faro in Chapter 6.
Assuming you have the cards in new deck order, give the deck a perfect Out Shuffle.
2. Next, cut the deck but retain the original top card on top via the Cover Up Cut.
3. Do another Cover Up Cut retaining the top card, then into another perfect Out Shuffle.
4. Continue cutting the deck retaining the top card on top each time until you have given it 8 perfect Out Shuffles.
5. Next, locate the suit that belongs to the top card. In other words, if the top suit was Clubs, you would locate the two of clubs, then cutting using the Cover Up Cut at the same time, the original Club suit would be on top plus the original Ace of Clubs also on top. The pack is again in its original order.
6. By using a cut that retains the tom card, the same results can bet obtained; however, the bottom cut may; be more deceptive as it is less apt to be seen, that is, if you want to use the action when completely surrounded. To I retain this bottom card use The Pull Down Move each time you cut the deck.
The following item is reprinted, with1 the permission of Howard P. Lyons from the IBIDEM, a magazine thai caters to cardicians of all tastes. It is a publication I recommend very highly to I all students of card magic.
The Faro Calculator
Where do I place the Aces if I want to I give the deck a Faro Shuffle but have the Aces come out at uneven numbers such as three or five? Or, how do I start if I want to give cards a Faro and have four cards distributed through the deck at certain definite odd and even numbers? How do I calculate a definite I number of cards between two selections using a Faro or two, or three?
Do these problems and others of similar nature make you reach for the slide rule or hire a mathematician? Then, here is a simple method for calculating positions of cards when using the Faro Shuffle system to set them.
1. First arrange a deck of cards in I numerical order and suit sequence. In other words, from top down, A to K of Clubs, A to K of Hearts, A to K of Spades, and A to K of Diamonds.
2. Let's assume your problem is to give the deck one Faro Shuffle but have the Aces come out every fifth card dealt.
3. Take your stacked deck, which is in CHSD order and numerical sequence. Cut at the 26th card which is the KH, then give it one perfect Faro Shuffle, making sure that the original top and bottom cards remain the same,
THE FARO CALCULATOR
for example, the AC remains on the top and KD remains on the bottom after the Faro Shuffle. (This, of course, is an Out Shuffle)
4. Hold the deck face down and thumb off five cards and then turn them face up. A 3 of Clubs will be at the face. As Clubs is the first suit of the sequence, this means that one Ace would have to be placed third from the top.
Thumb off another five cards, turn them face up onto the first batch, this is just to retain the order. A 5 of Spades turns up.
As Clubs and Hearts precede Spades, the 13 cards of the two suits must be added to 5 the numerical value of the card. This identifies the 5 of Spades' position before the Faro Shuffle. Therfore 13 plus 13 equals 26, and 26 plus 5 equals 31, or the position of the second Ace before a Faro Shuffle.
5. Thumb off a third set of five cards, which reveals an 8C. As Clubs is the first suit, this numerical value stands for the position of the next Ace, i.e., eight from the top.
6. The last set of five cards when turned face up reveals a 10S at the face. This means that again, all suits preceding it, each having a value of 13, are added to the value showing. In this case C equals 13, H equals 13, Spades value is 10. The result, 13 plus 13 plus 10 equals 36 would be the position of the final Ace.
7. If the Aces are now placed in 3831 and 36th position, then the deck cut at 26 and a perfect weave made, you will find that every fifth card dealt will be an Ace.
8. Using the above system, you can calculate any desired positions after the one shuffle.
As another example, suppose you want to know where to place the Aces so they will come out every third card after one Faro Shuffle.
Just thumb off three cards, noting which suits and values show up.
In this case, every third card would show first a 2C, second set 3S, third set 5C, fourth set 6S. The 2C and 5C, of course, show that two of the Aces would have to be in 2nd and 5th positions before the one Faro.
The 3S and 6S, adding 13 for each preceding suit, shows that the other two Aces would have to be in 29th and 32nd positions before the Faro.
9. Let us suppose you would like to give the deck two Faro Shuffles and still get the above results. In this case, just give your Calculating Deck another perfect Faro Shuffle but remembering to keep top and bottom cards, AC and KD, the same.
Now, going thru the same calculations as explained for one shuffle, you can get the positions of placement needed for two shuffles. This calculation will work for any number of shuffles. All you need do is decide on how many Faro Shuffles you want to give the deck to get certain cards into certain positions. Then give your Calculating Deck that many Perfect Shuffles. Finally, calculate, as given in the first instance, to learn where you need to originally place your desired cards so that they fall into the proper places after that number of Faro Shuffles.
We're sure that the user of the Faro Shuffles will find this an easy enough Calculating System.
Note: The above system has been explained using an Out Shuffle, but naturally the same calculations are applicable to In Shuffles as well as combinations of both In and Out Shuffles.
The Chain Calculator
Effect: Cardician shuffles the deck, yet after each shuffle he is able to tell the location of any card called for. To do the above effect, you need to use a memorized pack, ability to do perfect Faro Out Shuffles, plus a formula that enables you to use it like a Chain Calculator.
1. Let's assume you have memorized the order of the deck as per The MemoryStackbelow.
2. The formula for determining the new positions of a card after one Out Shuffle is as follows; any cards from numbers 1 to 26 will be doubled, minus one. In other words, a card at the 5th position times 2 equals 10, then minus 1 equals 9. The card originally 5th will now be 9th after one Out Shuffle.
On cards at numbers 27 to 52 you must subtract 26 from the position number, then double the remainder. For example, a card is, say, at the 30th position. Now 30 minus 26 is 4, then this doubled equals 8. Thus, the 30th card's new position is 8th from the top after the first shuffle.
3. That is fine, you say, for one shuffle, but how about each succeeding shuffle? Well, this is where the Chain Calculator System comes into play and works with a memorized pack simply because you know the card's original starting point when it is called.
4. Suppose you have just given the pack the third Faro Out Shuffle and now the spectator calls a card. As soon as he calls that card you immediately know its original memorized position. Let's assume the card he calls is the 10th card in the original memorized pack.
5. You immediately make your first calculation of a card from 1 to 26, i.e., double the position, minus one. This gives you 10 times 2 minus 1 which equals 19.
6. Now, 19 is the position after the first shuffle, but remember you gave it three shuffles. The next step is to again use the formula. As the card is 19, obviously you repeat the 1 to 26 formula of 19 times 2, minus 1 equals 37.
7. The 37 is the card's position after the second shuffle. This means you repeat the formula for a third time, However, as the card is now at 37, you use the formula for cards from 27 to 52 which is 37 minus 26 equals 11. Then, 11 times 2 equals 22. The card's position is now 22nd after the third shuffle,
8. Obviously the above process can be continued on thru the eight shuffles, but beyond the third shuffle it becomes quite a problem to calculate rapidly and accurately. Therefore, we now make use of a formula that will calculate the position of cards backward from the original memorized set.
9. In order to calculate the position of a card in, say, the 7th shuffle, the formula is this: On all cards in odd numl bered positions you divide by 2, then using the largest half will give the posi1 tion of the card. As an example, suppose the 15th card in the memorized list is called. Divide 15 by 2 which gives a larger half of 8; therefore, 8 is I the position of the card in the 7th shuf L fle,
10. For all cards at even numbers you divide the position by two, then add 26 to give you the new position. For example, the 38th card in the memorized list is called. Divide 38 which gives 19, then add 26 giving you 45 as the new I position of the card in the 7th shuffle.
11. To continue using the above as a Backward Chain Calculator, you simply repeat the formula. To give an illustration, suppose you wish to calculate a card's position in the 5th shuffle and the card's memorized position is originally 15. First, 15 is odd, so divide to get 8 (its position in the 7th shuffle.)
Now 8 is an even number, so you divide 8 to get 4, then add 26 to get 30 as the card's position (its position in the 6th shuffle.)
Continuing, 30 is even, so you divide 30 by 2 to get 15, then add 26 to get 41 as the card's position in the 5th shuffle.
12. Again, an example. This time taking our 38th card divide by 2 to get 19, add 26 to get 45 (7th shuffle). Now, 45 is odd, so you divide only by 2 to get 23 as the card's position (6th shuffle.) 23 is still odd, so again simply divide to get a larger half, 12 as the card's position in the 5th shuffle.
you have a good head for calculation, you should have no problem to get the positions throughout all shuffles. However, even if limited to three on each side of the original list, you still take care of seven of the shuffles.
You can easily bypass one or two or even three of the positions by merely shuffling till you get into the ones you are more familiar with.
At any rate, the whole point is that you can keep shuffling and yet apparantly keep track of all the cards.
The Left Over Faro Shuffle
This idea is dependent on the fact that it is possible to control several cards with an uneven or Left Over Faro Shuffle providing the cards to be controlled are known as well as their positions.
We will give an example of the process, but first let us define the terms Left Over Top Faro Shuffle and Let Over Bottom Faro Shuffle.
The Left Over Bottom Faro Shuffle is one in which an uneven cut is made, then the top half is weaved into the bottom half. However, the shuffle is started at the top of the two portions, with the original top card becoming second. In other words, an In Shuffle started at the Top, then running perfectly for as many cards as were cut off terminating in some cards being Left Over at the Bottom.
The Left Over Top Faro Shuffle is also one in which an uneven cut is made, then the top half is weaved into the bottom. This time the weave starts at the bottom of the two halves with the original bottom card becoming second. Again, it is an In Shuffle started at the Bottom, then running perfectly for as many cards as were cut off and terminating in some cards Left Over at the Top.
Besides the above information, it might as well be mentioned that either the Top or Bottom Faro can be of either the In or Out Shuffle type depending on the results required. Now, for an example of the use of this type of shuffle with regards to the control of four Aces.
If your cards are known as in the case of Aces you can use the idea of a Left Over Faro Shuffle as follows: Having placed Aces every 6th card via the side thumb count, you split deck at the last Ace, or the one in the 24th position, thus making this Ace the face card of the cut off packet. Now, do an In Shuffle so that the original top card will become the second from the top. However, due to the uneven cut, the original bottom four cards remain at the bottom during all the succeeding shuffles.
Cut again at the 24th position and you get an Ace at the face of the packet, then do another Left Over Bottom Faro Shuffle. If the pack is examined now, two Aces are the 23rd and 24th from the top. Another cut at 24, or the two
Aces together at the face of the cut off portion, a Left Over Bottom Faro Shuffle will bring the four Aces together starting at the 5th card from the bottom.
In case it is required to bring the Aces directly to the bottom after the above shuffle, merely pull upwards on the deck during the square up, so as to obtain a break above the bottom four cards. It is a simple matter to cut the bottom four cards to the top to leave the four Aces at the bottom.
In the case of the Aces being brought to the top, all you do is make sure the central Ace or Aces become the top card of the lower portion, then go into the Left Over Bottom Shuffle as described. The result will be four Aces on top in just three shuffles and the third one can be a regular riffle type just to throw them off.
The Left Over Top Faro would mean that the shuffle would be started at the bottom with the original bottom card being lost each time leaving the same cards Left Over on Top. Using this type, with the Aces as already explained, would mean that they could actually be brought to the bottom, or working the other way, they could be brought to 5678th positions from the top.
One other advantage to the Left Over Faro Shuffle is that while actually shuffling together the four Aces, another four cards of like value, such as four Kings, can be retained at top or botom during the shuffles.
By crimping the fourth card from the bottom you can use the Above Crimp Faro idea (See Chapter 6, Faro Shuffle) thus making the Left Over Faro a lot easier.
Shuffling The Aces
Effect: Four Aces are placed into the deck and seemingly lost. Each time the cardician shuffles the pack, he turns up an Ace on top even though it was conclusively not there previous to the shuffle.
The four Aces must be placed into the 14273747 positions from the top, For the present we will assume you have the Aces in those positions. Later on we will show how to get the Aces into the above positions very easily.
1. With the Aces apparently lost in the pack, show that they are not at top or bottom.
2. Split deck at 26, very easy as there is an Ace at 27th position, and give the pack an In Shuffle. This brings one Ace] to the top. Turn over the top card dealing it face up onto table as you say, "OneAce."
3. The above shuffle has automatically set the second Ace into the central position. All you need to do is again split deck at the Ace, then give the! pack an In Shuffle to bring the second Ace to the top.
4. During the second In Shuffles, youi will note that there will be one card left over at the bottom. In other words, the top portion of 25 cards will weave into the bottom portion of 27 cards. Mention is made of this in order that one doesn't think he has made a mistake at this point but is in reality doing a Left Over Bottom Faro.
5. Turn over the second Ace dealing it] to the table as you say, "The second Ace." Repeat showing top and bottom cards as not containing Aces.
6. Once again cut at the central doing another In Shuffle to bring the third Ace to the top. Deal it face up to table.
7. The fourth Ace is now in the central position so once more it becomes a simple matter to locate it and bring it to the top by another Faro In Shuffle,
This shuffle does not have to be perfect as long as the Ace ends up on top.
8. Once the fourth Ace is brought to the top you can deal it face up with the others; however, the following addition gives it a better climax.
9. Note the value of bottom card of the deck. Suppose it is a 9 spot. Make a top cut of about twenty cards so that in doing an In Shuffle, the top Ace will become second but the bottom card will remain the same. A second cut and shuffle will make the Ace 4th while a third shuffle and cut will make the Ace 8th from the top. The 9 spot has remained on the Dottom of the pack throughout.
10. Next, cut the 9 spot to the top, after which turn the top card face up. Act surprised that it isn't an Ace; however, quickly recovering say, "Well, it's a nine, so we will count down nine cards." Turn the nine spot face down, count to the 9th card, turn it face up to show the fourth Ace.
11. This method of Faro Shuffling while keeping the bottom cards intact can be used with any value card This idea is further discussed under "Exact Placement."
Now comes the problem of solving the placing the Aces into the needed positions of 14273747. It will be of interest to know that using the Faro Calculator we were able to determine the best opening positions for the Aces. These positions become 7404550.
In originally removing the Aces one should note the 6th card from the top. Now, when the Aces are reinserted, the pack can be held face up in readiness for the left thumb side riffle count. The first Ace to be found is placed into the third position from the face of the deck. The next two Aces are placed every fifth card. In other words, thumb count four, insert Ace, thumb count four, insert Ace (3rd). The fourth Ace is placed in front of the key card in the 7th position from the top. Turn deck face down, give deck one perfect In Shuffle. The Aces go to the 14273747th positions as needed for the effect. The Ace at 7 has moved to 14, the Ace at 40 moves to 27, the Ace at 45 moves to 37, while the Ace at 50 moves to 47 in the one In Shuffle.
Adding the principle of reversing cards with an overhand shuffle, it is possible to work the Aces into the needed positions even though the process is started at the top of the deck. To work, hold the pack face down and proceed to insert the Aces in the same identical manner but from the top. The first Ace, if you remember, is inserted into the third position, the next two Aces are inserted at intervals of four cards; however, for the fourth Ace you thumb count six cards, then insert the Ace into the 7th position.
The Aces are in positions 381320 from the top. In an overhand shuffle, run off the top 13 cards and throw the rest of the deck on top. This has now placed the Aces at 7404550. From here one In Shuffle places the Aces at 14273747 positions as needed for "Shuffling the Aces."
Placement Shuffle
Here is a use for the Faro Shuffle in which you place the 4 Aces in different parts of the deck, then after two Faro Shuffles, the aces will be together under the top nine cards. They naturally can be used in any effect such as the between 10 and 20 deal. The separation of the Aces plus the two Faro Shuffles should puzzle the knowitalls.
1. In taking out the Aces note and remember the 13th, 26th and 39th cards from the face of the deck. Assume these cards are the 13th2S, 26th3S, and 39th4S.
2. After the three key cards have been noted, cut the three face cards to the top of the deck.
3. Fan the deck or ribbon spread it on the table. Pick up the first Ace and insert it in back or to the left of the 13th key. In this case an Ace is placed in back of the 2S.
4. Second Ace is inserted in front of, or to the right of the 26th key, or in this instance the 3S.
5. The third Ace is placed one card in front of, or one card to the right of the 39th key, i.e., the 4S. In other words, the 4S, then one indifferent card, then the Ace.
6. Last Ace is placed into the fourth position from the top. Square the cards losing the Aces fairly.
7. To cut at 26, locate the center Ace, then release three cards onto the lower half before splitting deck. Out Shuffle leaving the top and bottom intact.
8. To cut at 26 again locate the original 39th key card or the 4S in this example. Cut to locate the 4S but release it onto the lower half. As the 3rd key really becomes the 27th card from the top, releasing it onto the lower section will give 26 cards in each half. Out Shuffle again leaving top and bottom cards intact.
9. Additional Faro Shuffles can be used to form a convincing combination yet distribute the Aces to every fourth card from the top as follows:
10. With the Aces already under the top nine cards give the pack an In Shuffe using a Throw Off Faro (See Chapter 6 for details on this) to bring Aces to 20222426 positions.
Cut at 26 or the last Ace, then give the pack an Off Center Faro to bring the alternating stock of Aces to the bottom of the deck.
12. Do an Overhand Shuffle to bring the stock of alternating Aces to the top, Cut an extra card over onto the top Ace, then give deck a Faro In Shuffle to finish with every Ace as fourth card among the top sixteen cards.
Control of the Aces
Using the Faro Calculator, we found that if Aces are placed at every 5th position from the top, you can get them to the top in five Faro In Shuffles. At First, this may seem like quite an undertaking, but it is the manner in which you do it that cuts down on the time element involved which is a great factor in the shuffles.
1. With the Aces face up on the table and the pack face down in the left hand, you are ready to insert the Aces one at a time into the deck.
2. With left thumb, riffle count the top four cards at the upper left corner. The right hand inserts an Ace at this point thus making it fifth from the top. The Ace is left projecting for half its length and should now cover the left thumb during the subsequent thumb counts of four cards each.
3. As before, the left thumb riffle counts four cards and the second Ace is inserted at this point. Follow the same proceedure with the next two Aces. The result is four Aces placed" into different portions of the pack, but actually, five cards apart at positions
4. Openly square up the pack pushing the Aces flush. Immediately split the deck for a Faro In Shuffle which brings the Aces into 10203040 positions. Again, split the deck and give it anothj er Faro In Shuffle.
5. The whole process of Step 4 is that you pushed Aces in flush, then gave it two shuffles to make sure they are lost,
6. At this point, you cover up the time needed by showing the Aces are not on the top or bottom. Spread the cards face up to show them widely separated.
7. You now give the pack two additional Faro Shuffles, saying, "Just in case you may think I remembered where the Aces are, I'll give the deck another shuffle" as you give the deck two Faro In Shuffles. Split the deck again, as you say, "How about one more just to be sure?" Naturally, the 5th In shuffle will get all four Aces to the top.
Using the principles of the Left Over Faro Shuffle, it is possible to start the Aces in the original 5101520 positions, then in only three shuffles get them together in the deck so that merely cutting at that point will get all four Aces to the top or bottom as needed. The following is a brief outline of the action.
1. Aces placed every 5th card via the thumb riffle count.
2. A Faro In Shuffle is made, bringing Aces to 10203040 positions.
3. Now, a cut is made at the known Ace in 20th position so that this Ace becomes the face card of the 20 card packet. Now do a Left Over Bottom Faro Shuffle of either the In or Out type to bring the Aces to the 19th and 20th positions and the 39th and 40th positions. This second shuffle brings each two Aces together.
4. Cut the deck again at the 20th Ace making this the face card of the packet. Under this Ace will be the second Ace.
5. Again, do a Left Over Bottom Faro Shuffle of either the In or Out type to bring all four Aces together at 40393837 positions from the bottom.
6. A cut where the Aces are and you can bring them to either the top or bottom. You can add to the spectator's confusion by undercutting half the pack and in an overhand shuffle, reversing this position so that the Aces become 13141516 from the top. Another overhand shuffle to run off the top 12 cards will bring the Aces to the top.
It might be mentioned that at times, a combination of Faro Shuffles, Riffle Shuffles and Overhand Shuffles can cxpedte rev tine the top. As an example, suppose you have just Faro'd the Aces into 9th and 10th positions and 19th and 20th positions from the top. All you need do is overhand shuffle to run off eight cards, thus bringing the first pair of Aces to the top. Now, a cut at the second pair of Aces, plus a riffle shuffle will enable all Aces to be controlled to the top. Also, the Aces can be controlled strictly through the use of an overhand cull shuffle to get the two pairs of Aces together to the top.
An Out Shuffle Effect
Effect: A selected card has been lost in the pack. The pack is cut several times, then the top card is turned over. Its value is used to count down into the pack. This second card matches the value of the first card. It, too, is used to count down further into the pack, where the selection is found to be. This effect is a good example of how an Out Shuffle can be used.
Have a pair of eights secretly on bottom of the pack.
2. Have a card selected and on its return, undercut the pack so as to get the pair of 8's over the selection, but, of course, at this time you merely keep a break over the selected card.
3. Release the two eights so they fall onto the selection, then double cut to the break, thus bringing the pair of eights to the top with the selection under them.
4. Now, give the pack three Out Shuffles which will retain one eight on top. The second eight will become eight cards away from the top card, also an eight. The selection will be eight cards away from the second eight.
5. A couple of false cuts to retain the top stock, may be in order here. Eventually, turn over the top card to show an eight. Place this eight aside, face up onto the table.
6. Count down eight cards from the top of the pack to turn up the second eight. Place this eight face up onto the first tabled eight as you remark about the coincidence.
7. Count down eight more cards to reveal the selection.
8. An additional subterfuge can be added. After the three Faro Out Shuffles, undercut the pack for an Overhand Shuffle. Run 12 cards onto the top, injog and shuffle off. Cut at the injog and cut or throw. This means there are twelve unknown cards over the first eight spot.
9. turn over the cards face up as you say, "One of these cards should tell me something." All you do is use the old dodge of repeating to yourself, KQJ10etc., as you deal the cards face up. When you come to a card identical in value to what you are saying, you use it to count down into the pack. Naturally, this will bring you to the first eight spot. From here, the proceedure is automatic.
You can use Bob Hummer's idea of repeating three values for each card turned up, thus insuring that you will get to a card you can use; however, it isn't really necessary as eventually you will come to the first eight spot anyway.
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